I found this on Quora. What would the standard algorithm be, I wonder.
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There may be other solutions. a = b = 3, c = 21. (Egyptian Fractions)
Filed under arithmetic, fractions, math, operations
Tagged as arithmetic, construction, fractions, heuristic
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Your posts always get me thinking!
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I like 1/2 + 1/7 + 1/14 better since it has a larger smallest piece. Nobody wants to get a pile of crumbs.
To me the standard algorithm is the greedy one — but it can result in horrendously big denominators sometimes, and often doesn’t give a 3-fraction sum even when such a sum exists.
There are lots of unsolved problems even in such a simple situation as this! Look up Erdos-Strauss for instance.